hello, I knitting a sweater, but part of pattern do not understand, could someone help me? and sorry for my bad English and thanks
Pattern:
Shape raglan armholes
Kepping patt corret, cast off 6 sts at beg of next two rows
74 (80:84:90:94:102) sts.
Work 4 (2:0:0:0:0) rows.
Next row (RS): K2tog, patt to last 2 sts, K2tog tbl. [this is okay, I understand this]
This is the problem:
Working all decreases as set by last row, dec 1 st at each end of 6th (4th:2nd:2nd:2nd:2nd) and 1 (0:0:0:0:0) foll 6th row, then on foll 0 (0:2:4:7:13) alt rows, then on 11 (14:14:14:13:11) foll 4th rows
46 (48:48:50:50:50) sts.
Are you confused by the 1(0, 0, 0, 0…) parts?
This pattern gives directions for several sizes. The first number is usually for the smallest size, so you would follow those to make the smallest. If you read through those parts of the pattern, count over to the size you’re making and mark the direction for that size with a highlighter–say you’re making the third size; you’d mark the thirds set of directions. It’ll save you a lot of time.
The other thing beginners get hung up on is the (102 stitches) at the end of a line. That’s telling you that you have that many stitches when the row is worked correctly, and doesn’t mean you need to add that many or anything like that.
After the armhole bind off of 6sts twice you have 74sts. Then work 4 rows and dec one stitch at each end, leaving you with 72sts.
Now work 5 rows and dec at each end of the 6th and again, work 5 rows and dec at each end of the 6th. You’ll be down to 68sts. Dec at each end of the 4th row 11 times (work 3 rows and dec on the 4th) and you’ll end with 46sts.
Each decrease row lowers the stitch count by 2sts.
