# Decreasing number of cast-on sts

I’m trying to figure out how to decrease the number of C/O stitches in this pattern. I can’t figure it out (this could be due to the fact that I slept through most of my algebra classes).

C/O 234 sts

Pattern:
R1: Knit
R2: k4, purl to last 4 sts, k4
R3: k4, *k2, yo, p1, p3tog, p1, yo; rep from * to last 6 sts, k6
R4: k4, purl to last 4, k4.

The original pattern makes a blanket that is 49"x60", I want to make it a baby blanket, maybe around 25"x35-40".

What is your stitch gauge? AKA: how many stitches are in the 4" swatch? How many rows are in the 4" swatch?

Well, anyhoo…here is what I’d do:

Knit the recommended swatch…as set forth by the designer.

Using YOUR SWATCH as a measuring guide…just cast on the number of stitches that will make the blanket 25" wide.

So, if your yarn renders 20 st = 4"…cast on 120 stitches to make the blanket about 24" wide. Cast on 140 st to make the blanket 28" wide.

(I got this by multiplying 20st x6 to make the 24" width…and 20st x7 to get the 28" width.)

The length makes no diff…you just bind off when you are satisfied!

But if I did what you’re suggesting, I wouldn’t be able to work the pattern. The third row is what is the problem, I need to decrease by a certain number of stitches (as an example, a multiple of 7) to be able to work the pattern. (k4, *k2, yp, p1, p3tog, p1, yo; rep from * to last 6, k6).

The pattern doesn’t say what multiple to cast on to make the blanket larger or smaller and like I said, I’m not so good at the math. LOL.

Edited to add: All I really need is the multiple of sts to decrease by. I guess I should have put that in my original post. Sorry!

Oh!

Well, still…the same principle could apply.

Let’s see…hmmm…

Oh, I know…if, for example 140 st st would equal 28"…then that is ABOUT your targeted number of cast on stitches.

How many stitches are involved in each width-wise repeat?
Divide that number into 140.

Example: if your repeat is 7 stitches wide…140 divided by 7 is 20 repeats exactly.

So if you cast on 150…you will have those first [B]4[/B] knits…then 20 repeats…then those last [B]6[/B], too.

Does this make any sense?

This is as close as I can come to a solution for you! I think it will work for you. Of course, I don’t know the ‘weight’ of your yarn.
But, if it is a worsted weight…this will work out to be about a 30" wide blanket.

I think so. What I ended up doing was writing it all out until I got to a number I was satisfied with. And that was 150. LOL.

Thank you!

Hey, waaaay to go little lovemuppet!
Where there’s a will, there’s a way!!

Yes, you have to get the multiple involved in the repeats. Since it seems to be 7 plus the 10 edge sts, figure how many sts you’ll need for 30", subtract 10 and see how close that number is to a multiple of 7. If it’s not exact, add that many more (and don’t forget the 10sts
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